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Archive · November 1, 2026

Grade 5 Math: 10 Free Practice Questions

A brand-new set of Grade 5 math practice questions every single day, with the answer and a full explanation for each one. No account, no paywall — tap an answer to check it.

1Which value of the exponent n makes the equation 0.6 multiplied by 10^n = 600 true?

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Answer: n = 3
0.6 times 1,000 (10^3) equals 600, so n = 3.

2A rectangular garden is 31 units long and 12 units wide. What is its perimeter?

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Answer: 86 units
<p><strong>CORRECT ANSWER: 86 units</strong></p><ol><li>Add the length and the width: 31 + 12 = 43.</li><li>Double that sum because <span style='background:#fef08a;padding:2px 6px;border-radius:4px;font-weight:bold;'>perimeter</span> goes around both pairs of sides: 2 × 43 = 86.</li><li>The perimeter is <span style='background:#bbf7d0;padding:2px 6px;border-radius:4px;font-weight:bold;'>86 units</span>.</li></ol><div style='background:#dbeafe;border-left:4px solid #3b82f6;padding:10px 14px;border-radius:6px;margin-top:10px;'><strong>Remember:</strong> Perimeter of a rectangle is 2 × (length + width)!</div>

3A number is divided by 5, then 3 is added, giving a result of 9. What is the number?

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Answer: 30
Correct Answer: 30. Formulate the equation: (x / 5) + 3 = 9. First, isolate the division term by applying the inverse operation of addition (subtracting 3 from both sides): x / 5 = 6. Next, solve for x by applying the inverse operation of division (multiplying both sides by 5): x = 30.

4Evaluate (p × 2) + (p × 3) when p = 6.

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Answer: 30
<p><strong>Step-by-step Solution:</strong></p><ol><li>First, substitute the given numerical value (6) for the variable (p) in the algebraic expression: (6 &times; 2) + (6 &times; 3).</li><li>Apply the standard order of operations (PEMDAS/BODMAS), ensuring operations within parentheses are evaluated first: (6 &times; 2) = 12 and (6 &times; 3) = 18.</li><li>Perform the final addition operation: 12 + 18 = 30.</li></ol>

5Point J is plotted on the coordinate grid below. What is the ordered pair for point J?

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Answer: (0, 5)
Point J is located 0 units to the right of the origin along the x-axis and 5 units up along the y-axis, so its ordered pair is (0, 5). The x-coordinate is always listed first.

6A bicycle wheel has a radius of 13 inches. Using π ≈ 3.14, how far does the wheel travel in one full rotation (its circumference)?

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Answer: 81.64 inches
<p><strong>CORRECT ANSWER: 81.64 inches</strong></p><ol><li>Double radius for diameter: 2 × 13 = 26.</li><li>3.14 × 26 = <span style='background:#fef08a;padding:2px 6px;border-radius:4px;font-weight:bold;'>81.64</span>.</li><li>The distance is <span style='background:#bbf7d0;padding:2px 6px;border-radius:4px;font-weight:bold;'>81.64 inches</span>.</li></ol><div style='background:#dbeafe;border-left:4px solid #3b82f6;padding:10px 14px;border-radius:6px;margin-top:10px;'><strong>Remember:</strong> C = 2πr when radius given!</div>

7Mia spent $18 and has $32 left. How much money did she start with?

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Answer: $50
Work backward: $32 + $18 = $50.

8Evaluate (k + 5) ÷ 3 when k = 7.

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Answer: 4
<p><strong>Step-by-step Solution:</strong></p><ol><li>First, substitute the given numerical value (7) for the variable (k) in the algebraic expression: (7 + 5) &divide; 3.</li><li>Apply the standard order of operations (PEMDAS/BODMAS), ensuring operations within parentheses are evaluated first: (7 + 5) = 12.</li><li>Perform the final division operation: 12 &divide; 3 = 4.</li></ol>

9Four friends equally share 1/2 gallon of juice. What fraction of a gallon does each friend receive?

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Answer: 1/8 gallon
1/2 ÷ 4 = 1/2 x 1/4 = 1/8 gallon.

10A printing company prints 432 pages every hour for 15 hours, then bundles them into packets of 48 pages each. How many packets are made?

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Answer: 135
<p><strong>Step-by-Step Solution:</strong></p><p>This is a multi-step word problem requiring multiplication followed by division.</p><ol><li><strong>Calculate the Total Pages:</strong> Multiply the hourly production rate by the total number of hours.<br>432 pages/hour &times; 15 hours = <strong>6,480</strong> total pages.</li><li><strong>Calculate the Number of Packets:</strong> Divide the total number of pages by the capacity of a single packet.<br>6,480 &divide; 48 = <strong>135</strong>.</li></ol><p>The company will make exactly <strong>135</strong> packets.</p>

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