1Marcus has 16 crayons to split evenly among 3 groups. Each group gets as many whole crayons as possible, with some left over. How many more crayons would Marcus need to buy so that ALL 3 groups can have exactly 6 crayons each, with none left over?
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Answer: 2
Step 1: 16 crayons divided among 3 groups (16 ÷ 3) = 5 Step 2: crayons left over after giving every group 5 (16 − 3 × 5) = 1 Step 3: more crayons needed so the leftover group also gets 6 like a full group would need (3 − 1) = 2 Step 4: total extra crayons needed to make every group's share equal (2 × 1, since each missing group needs exactly 1 more) = 2 So the answer is 2 — extra crayons needed.
Step 1: 16 crayons divided among 3 groups (16 ÷ 3) = 5 Step 2: crayons left over after giving every group 5 (16 − 3 × 5) = 1 Step 3: more crayons needed so the leftover group also gets 6 like a full group would need (3 − 1) = 2 Step 4: total extra crayons needed to make every group's share equal (2 × 1, since each missing group needs exactly 1 more) = 2 So the answer is 2 — extra crayons needed.